|
a. Use the result in Exercise 9 to show that if A−1 exists and x, y ∈ Rn, then (A + xyt)−1 exists if and only if ytA−1x ≠ −1.
b. By multiplying on the right by A + xyt, show that when ytA−1 x = −1 we have |
| New search. (Also 1294 free access solutions) |