A lake is stocked with 640 fish of a new variety. The size of the lake, the availability of food, and the number of other fish restrict the growth of that type of fish in the lake to a limiting value of 3040. The population of fish in the lake after time t, in months, is given by the function
P(t) = 3040 / (1 + 3.75e-0.32t)
a) Graph the function.
b) Find the population after 0, 1, 5, 10, 15, and 20 months.
1) You can buy this solution for 0,5$.
2) The solution will be in 8 hours.
3) If you want the solution will be free for all following visitors.
4) The link for payment paypal.me/0,5usd
5) After payment, please report the number of the task to the oneplus2014@gmail.com
New search. (Also 1294 free access solutions)
Use search in keywords. (words through a space in any order)